If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3r^2-60=3r
We move all terms to the left:
3r^2-60-(3r)=0
a = 3; b = -3; c = -60;
Δ = b2-4ac
Δ = -32-4·3·(-60)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-27}{2*3}=\frac{-24}{6} =-4 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+27}{2*3}=\frac{30}{6} =5 $
| 2x-5=9;x=7 | | 2x+5)/11=x-4 | | 14x-6=9x+44 | | -6=6n-3n | | p-0.40p=470 | | 16=8^-x-4 | | 3(x-2)-4(3-x)=3 | | 4x+30=40+2x | | 1/3(9x+12)=30 | | 5k-6=8k+3 | | 4/5x=x+10/3 | | 23x=58 | | 8.50x+15=6x | | 18=8x-6+4x | | 16+5x+10x+14=180 | | 52=(2x-2)+2 | | 37=2v+11 | | –2(6x-3)=42 | | 2(x+3)-5(x-1)=3x-4(x-1) | | 18t=10(15+t) | | 470=p-0.40p | | 4(x-2)=8(x+2) | | 3(x2-4x)=x+10 | | 7x+7=12×+2 | | 4m-6=5m-1 | | 2w+16=7w | | 3x-48=72 | | 0.25q+0.10(2q+3)=10.65 | | 4x+6=-2x-2-12 | | 15=12-6(2-2w) | | 11-x=16+4x | | 180=90+45+x |